Re: coin toss

BlankMondragon <blankmondragon@[EMAIL PROTECTED]
> wrote:

: show disgrega duplica :many.throws
: [[1 1] [0 0] [1] [0 0] [1] [0] [1 1 1 1] [0] [1 1] [0 0 0] [1 1 1 1 1 1
: 1] [0] [1 1 1] [0] [1] [0] [1 1] [0 0] [1] [0] [1] [0] [1 1 1] [0 0 0 0
: 0] [1 1 1] [0 0 0 0 0] [1 1] [0 0 0] [1 1] [0] [1] [0] [1] [0 0] [1 1
: 1] [0 0] [1 1] [0 0] [1 1] [0 0] [1] [0] [1] [0] [1 1] [0 0] [1 1 1 1
: 1] [0] [1 1 1]]


Using the combinations formula (2 ^ 5 = 32) and saying that you're looking
for 2 of the combinations (all heads or all tails/all 0's all 1's)
you want 2 out of 32 or 2/32 = 1/16 = .0625 or 6.25%.

In looking at what you have above, you found 5 ones in a row 4 times
(you found 7 in a row, which has 3 groups of 5 in a row) and 5 zeroes 
2 times, for a total of 6.  

Got to love it when math works :-)


: show simul 5
: 0.975

: show simul 6
: 0.84

: show simul 7
: 0.548

: show simul 8
: 0.3

: show simul 9
: 0.15

: show simul 10
: 0.081

: Daniel
: http://mondragon.angeltowns.net/logofe/

: PS. This page is about a simulation of the Birthday paradox:
: http://mondragon.angeltowns.net/paradiso/Problema***pleanos.html


-- 

-davec
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