by Duane Bozarth <dpbozarth@[EMAIL PROTECTED]
>
Sep 9, 2005 at 06:50 PM
Dave Chamberlain wrote:
>
> BlankMondragon <blankmondragon@[EMAIL PROTECTED]
> wrote:
>
> : show disgrega duplica :many.throws
> : [[1 1] [0 0] [1] [0 0] [1] [0] [1 1 1 1] [0] [1 1] [0 0 0] [1 1 1 1 1
1
> : 1] [0] [1 1 1] [0] [1] [0] [1 1] [0 0] [1] [0] [1] [0] [1 1 1] [0 0 0
0
> : 0] [1 1 1] [0 0 0 0 0] [1 1] [0 0 0] [1 1] [0] [1] [0] [1] [0 0] [1 1
> : 1] [0 0] [1 1] [0 0] [1 1] [0 0] [1] [0] [1] [0] [1 1] [0 0] [1 1 1 1
> : 1] [0] [1 1 1]]
>
> Using the combinations formula (2 ^ 5 = 32) and saying that you're
looking
> for 2 of the combinations (all heads or all tails/all 0's all 1's)
> you want 2 out of 32 or 2/32 = 1/16 = .0625 or 6.25%.
>
> In looking at what you have above, you found 5 ones in a row 4 times
> (you found 7 in a row, which has 3 groups of 5 in a row) and 5 zeroes
> 2 times, for a total of 6.
>
> Got to love it when math works :-)
....
But OP wanted a run of 6 to be only one "event" when I asked what
comprised a "run of five"...
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