by Duane Bozarth <dpbozarth@[EMAIL PROTECTED]
>
Sep 13, 2005 at 11:49 PM
BlankMondragon wrote:
>
> > But OP wanted a run of 6 to be only one "event" when I asked what
> > comprised a "run of five"...
>
> In the simulation I showed a run of 6 as only one event.
>
Yes, I was commenting back to Dave Chamberlain who noted a run of 7 as
"3 runs of 5" when doing his calculations of P(5 H|T) independently that
that didn't follow the rules as outlined by OP.
I had noted a similar approach some time much earlier in looking at the
100 tosses as a series of 96 independent sets of 5 but when OP responded
that a run of N >= 5 is to be counted as on run, that eliminates that
simplification.
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